Some fundamental division details are wanted to comply with for dividing numbers. The repeated subtraction of the identical quantity is expressed by division briefly kind and in lengthy kind.

Share 12 pencils between 2 youngsters. To seek out what number of pencils

every baby will get, we begin giving 1 pencil to every baby till we’re left

with no pencils.

This implies 12 pencils have been divided into 2 teams of 6

pencils. Every baby will get 6 pencils.

It signifies that there are 2 teams of 6.

Â Â Â Â Â Â Â Â That is written as **12 Ã· 2 = 6**

That is referred to as a division reality.

Let there be 12 mangoes. These mangoes are to be distributed equally amongst 4 boys.

Allow us to distribute 12 mangoes among the many 4 boys individually to have the mangoes. To start with one mango is positioned for every boy.

We see that various mangoes are left. Then one other mango is positioned for every boy. Nonetheless there are mangoes left.

Now a 3rd mango is positioned for every boy. Now every boy has 3 mangoes and no mango is left exterior.

On including the mangoes for every boy we get;

3 mangoes + 3

mangoes + 3 mangoes + 3 mangoes = 12 mangoes

It means:

3 mangoes 4 instances = 12 Â Â Â Â Â Â Â Â Â Â Â

or, 3 Ã— 4 = 12

It proves the

multiplication reality 3 Ã— 4 = 12. Once more if we take away 3 4 instances from 12 we

get zero.

It means 12 â€“ 3,

4 instances = 0, 12 Ã· 3 = 4

or, 12 Ã· 4 = 3

Therefore we get,

(i) 3 4 instances

or 4 instances 3 exhibits the multiplication reality:

3 Ã— 4 = 12

or, 4 Ã— 3 = 12

(ii) 3 taken out

4 instances exhibits the essential division reality:

12 Ã· 3 = 4

or, 12 Ã· 4 = 3

Thus, distributing

equally or making teams of equal variety of objects exhibits the division reality.

(i) Including the

identical quantity repeatedly exhibits multiplication reality:

(3 + 3 + 3 + 3 =

4 Ã— 3 = 12)

(ii) Subtracting

the identical quantity repeatedly exhibits division reality:

(12 â€“ 3 â€“ 3 â€“ 3 â€“

3 = 0; 12 Ã· 3 = 4)

Thus, the method

of division is the inverse of multiplication and the method of multiplication

is the inverse of division.

Subsequently, we

additionally know that;

(i) 3 Ã— 4 = 12

offers two division details as 12 Ã· 3 = 4 and 12 Ã· 4 = 3

(ii) 12 Ã· 3 = 4

offers two multiplication details as 3 Ã— 4 = 12 and 4 Ã— 3 = 12.

**Establish the dividend, divisor and the quotient within the
given division assertion.**

Allow us to recall a few of the vital details about division.

- Division means splitting into equal teams.
- Division is repeated subtraction.
- Division is inverse of multiplication.

In a division sum of the quantity to be divided is known as theÂ **dividend**. The quantity by which we divide is known as theÂ **divisor**. The results of divisor is known as theÂ **quotient**.

**Overview of Division :**

â€¢ After we make equal teams, we use division.

â€¢Â The signal of division is Ã·

â€¢Â A quantity divided by itself equals to 1.

e.g. 7 Ã· 7 = 1Â orÂ 4 Ã· 4 = 1Â orÂ 9Â Ã· 9 = 1

â€¢Â A quantity divided by 1 equals to the quantity itself.

e.g. 2 Ã· 1 = 2Â orÂ Â 5 Ã·Â 1 = 5Â orÂ Â 8 Ã·Â 1 = 8

â€¢ Zero divided by any quantity equals to zero.

e.g. 0 Ã· 3 = 0Â orÂ Â 0 Ã· 6 = 0Â orÂ 0 Ã· 10 = 0

**Questions and Solutions onÂ Fundamental Division Information:**

**I. Write the division details utilizing the division image for
every image.**

(i) Share 8 erasers between 2 youngsters.

(ii) Share 4 scissors between 2 youngsters.

(iii) Share 14 keys

between 2 youngsters.

(iv) Share 12 pens

between 2 youngsters.

**Reply:**

**I.** (ii) 4Â Â Ã· 2 = 2

(iii) 14 Ã· 2 = 7

(iv) 12 Ã· 2 = 6

**II. Fill within the blanks –**

(i) 0 Ã· 5 = _____

(ii) 0 Ã· 6 = _____

(iii) 0 Ã· 8 = _____

(iv) 0 Ã· 9 = _____

(v) 4Â Ã· 1 = _____

(vi) 3Â Ã· 1 = _____

(vii) 2Â Ã· 1 = _____

(viii) 6Â Ã· 1 = _____

(ix) 2 Ã· 2 = _____

(x) 5Â Ã· 5 = _____

(xi) 6Â Ã· 6 = _____

(xii) 8Â Ã· 8 = _____

(xiii) 7 Ã· 1 = _____

(xiv) 3Â Ã· 3 = _____

(xv) 0Â Ã· 2 = _____

(xvi) 6Â Ã· 1 = _____

(xvii) 8Â Ã· 1 = _____

(xviii) 9Â Ã· 1 = _____

(xix) 0Â Ã· 4 = _____

(xx) 5Â Ã· 1 = _____

(xxi) 0Â Ã· 3 = _____

(xxii) 0Â Ã· 7 = _____

(xxiii) 9Â Ã· 9 = _____

(xxiv) 1Â Ã· 1 = _____

**Reply:**

**II.Â **(i) 0

(ii) 0

(iii) 0Â

(iv) 0

(v) 4

(vi) 3

(vii) 2

(viii) 6

(ix) 1

(x) 1

(xi) 1

(xii) 1

(xiii) 7

(xiv)1

(xv) 0

(xvi) 6

(xvii) 8

(xviii) 9

(xix) 0

(xx) 5

(xxi) 0

(xxii) 0

(xxiii)Â 1

(xxiv) 1

**III. Fill within the blanks –**

(i) 6 Ã· _____ = 6

(ii)Â 2 Ã· _____ = 2

(iii)Â 2 Ã· _____ = 1

(iv)Â 4 Ã· _____ = 0

(v) _____ Ã· 9 = 0

(vi) _____ Ã· 8 = 1

(vii) _____ Ã· 3 = 3

(viii) _____ Ã· 2 = 1

(ix) 5 Ã· _____ = 1

(x) 7 Ã· _____ = 1

(xi) 6 Ã· _____ = 6

(xii) 1 Ã· _____ = 3

(xiii) _____ Ã· 7 = 0

(xiv) _____ Ã· 1 = 8

(xv) _____ Ã· 6 = 1

(xvi) 6 Ã· _____ = 0

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