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right here discover the perimeter of a triangle. We all know perimeter of a triangle is the

whole size (distance) of the boundary of a triangle.

Perimeter of a triangle is the sum of lengths of its three

sides.

For instance, perimeter of the ∆PQR = PQ + QR + RP

**●** The perimeter of a triangle ABC

= AB + BC + CA

= 2 cm + 4 cm + 3 cm,

(add the size of every aspect of the triangle).

= 9 cm

Perimeter of the triangle = Sum of the perimeters.

*The perimeter of the triangle = Sum of the lengths of three sides.*

Allow us to contemplate a number of the examples on perimeter of a triangle:

**1.** Discover the perimeter of

a triangle having sides 3 cm, 8 cm and 6 cm.

**Answer:**

Perimeter of a triangle

= Sum of all of the three sides

= AB + BC + AC

= 3 cm + 8 cm + 6 cm

= 17 cm

**2.** Discover the perimeter of the triangle PQR whose sides are 4

cm, 6 cm and eight cm.

**Answer:**

Within the determine PQ = 4 cm, PR = 6 cm and QR = 8 cm

The perimeter of the rectangle PQR

= 4 cm + 6 cm + 8 cm

= 18 cm

**3.** Discover the perimeter of an equilateral triangle whose one

aspect is 5 cm.

**Answer:**

A triangle during which all the perimeters are equal known as an

equilateral triangle.

Perimeter of the equilateral triangle = 3 × aspect

= 3 × 5 cm

= 15 cm

Thus, perimeter = 15 cm.

**4.** Discover the perimeter of a triangle whose size of three sides are 8 cm, 11 cm, 13 cm.

**Answer:**

To seek out the perimeter of the triangle, we add all the perimeters collectively.

Perimeter of a triangle

= Sum of all of the three sides

= 8 cm + 11 cm + 13 cm

= 32 cm

**5.** Discover the perimeter of a triangle whose sides are 5 cm, 2 cm

and three cm.

**Answer:**

Perimeter of the triangle is the sum of the lengths of its

sides.

Perimeter = 5 cm + 2 cm + 3 cm

Thus, perimeter = 10 cm.

**6.** Discover the perimeter of every triangle.

**Answer: **

(i) Perimeter of ∆XYZ = 5.5 cm + 6 cm + 6 cm = 17.5 cm

(ii) Perimeter of ∆ABC = 8 cm + 6 cm + 6 cm = 20 cm

(iii) Perimeter of ∆PQR = 4 cm + 3 cm + 5 cm = 12 cm

**7.** Discover the perimeter of the given shapes.

**Answer:**

(i) Perimeter = PQ + QR + RS + ST + TU + UV + VP

= 2.5 cm + 3 cm + 2 cm + 3 cm + 2.5 cm + 4 cm + 4

cm

=

21 cm

(ii) Perimeter = PQ + QR + RS + SP

= 4 cm + 4 cm + 4 cm + 4 cm

= 16 cm

(iii) Perimeter = PQ + QR + RS + ST + TP

= 7 cm + 6 cm + 4 cm + 3 cm + 5 cm

= 25 cm

**Phrase Issues on Perimeter of a Triangle:**

**1.** Two sides of a

triangle are 3 cm and 4 cm. Discover the third aspect of the triangle if its

perimeter is 11 cm.

**Answer:**

First aspect of the triangle = 3 cm

Second aspect of the triangle = 4 cm

Perimeter of the triangle = Sum of the lengths of sides

i.e. sum of the lengths of the perimeters = 11 cm

3 cm + 4 cm + size of the third aspect = 11 cm

7 cm + size of the third aspect = 11 cm

However we all know that 7 cm + 4 cm = 11 cm (*Notice: 11 –
7 = 4*)

Due to this fact, size of the third aspect = 4 cm

**Questions and Solutions on Perimeter of a Triangle:**

**1.** A triangle has a fringe of fifty cm. If its two sides

are of lengths 15 cm and 19 cm, what’s the size of the third aspect?

**Reply:** 16 cm

**● ****Associated Ideas**

**● ****To
Measure the Size of a Line-segment**

**● ****Examples
on Unit of Mass or Weight**

**● ****Items
for The Measurement of Capability**

**● ****Examples
on Measurement of Capability**

**● ****Antemeridian
(a.m.) or Postmeridian (p.m.)**

**● ****Calendar**

**● ****Studying
and Decoding a Calendar**

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